state[1] = 0xefcdab89L;
state[2] = 0x98badcfeL;
state[3] = 0x10325476L;
}
private long F(long l, long l1, long l2)
{
return l & l1 | ~l & l2;
}
private long G(long l, long l1, long l2)
{
return l & l2 | l1 & ~l2;
}
private long H(long l, long l1, long l2)
{
return l ^ l1 ^ l2;
}
private long I(long l, long l1, long l2)
{
return l1 ^ (l | ~l2);
}
private long FF(long l, long l1, long l2, long l3, long l4, long l5, long l6)
{
l += F(l1, l2, l3) + l4 + l6;
l = (int)l << (int)l5 | (int)l >>> (int)(32L - l5);
l += l1;
return l;
}
private long GG(long l, long l1, long l2, long l3, long l4, long l5, long l6)
{
l += G(l1, l2, l3) + l4 + l6;
l = (int)l << (int)l5 | (int)l >>> (int)(32L - l5);
l += l1;
return l;
}
private long HH(long l, long l1, long l2, long l3, long l4, long l5, long l6)
{
l += H(l1, l2, l3) + l4 + l6;
l = (int)l << (int)l5 | (int)l >>> (int)(32L - l5);
l += l1;
return l;
}
private long II(long l, long l1, long l2, long l3, long l4, long l5, long l6)
{
l += I(l1, l2, l3) + l4 + l6;
l = (int)l << (int)l5 | (int)l >>> (int)(32L - l5);
l += l1;
return l;
}
private void md5Update(byte abyte0[], int i)
{//补位操作，abyte0为需要进行MD5加密的字符串，i为字符串长度；
byte abyte1[] = new byte[64];
int k = (int)(count[0] >>> 3) & 0x3f;
if((count[0] += i << 3) < (long)(i << 3))
count[1]++;本新闻共 6页,当前在第 2页 1 2 3 4 5 6
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